決賽安排 - potential problem
This is the proposed 決賽安排
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每組首三名進行單淘汰比賽 (同時同地與其餘兩隊一齊打, 不論勝負打足五塲)
計分方法如初賽一樣, 出場人數得一分, 每勝一場得兩分. (若只安排3人出賽, 便是連勝兩場 3:2, 總分也可能會輸)
是次比賽將不進行遺材賽事, 換言之 4-9 名不用再打
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Potential Problem
I believe the original proposal have a number of issues
Scenario #1
Let's say we have Team A, B, C and the results as follows:
Team A beats Team B by 3:2
Team A beats Team C by 3:2
Team B beats Team C by 5:0
Then the total points scored will be:
Team A: 22 points
Team B: 24 points
Team C: 14 points
In the above situation although Team A beats both Team B & C, Team A ends up second while Team B becomes champions when they won 1 and lost 1.
Scenario #2
Let's say we have Team A, B, C and the results as follows:
Team A beats Team B by 3:2
Team A beats Team C by 3:2
Team B beats Team C by 4:1
Then the total points scored will be:
Team A: 22 points
Team B: 22 points
Team C: 16 points
In the above situation which team will become champions since both Team A & B have 22 points each? We need a more detail "tie break" description to determine which team will become champions.
[ 本帖最後由 wlwlwl 於 2009-11-27 10:12 編輯 ]
