發新話題
打印

決賽安排 - Problem

決賽安排 - Problem

決賽安排 - potential problem

This is the proposed 決賽安排
===============================================
每組首三名進行單淘汰比賽 (同時同地與其餘兩隊一齊打, 不論勝負打足五塲)
計分方法如初賽一樣, 出場人數得一分, 每勝一場得兩分.  (若只安排3人出賽, 便是連勝兩場 3:2, 總分也可能會輸)
是次比賽將不進行遺材賽事, 換言之 4-9 名不用再打
===============================================

Potential Problem
I believe the original proposal have a number of issues

Scenario #1
Let's say we have Team A, B, C and the results as follows:
Team A beats Team B by 3:2
Team A beats Team C by 3:2
Team B beats Team C by 5:0

Then the total points scored will be:
Team A: 22 points
Team B: 24 points
Team C: 14 points
In the above situation although Team A beats both Team B & C, Team A ends up second while Team B becomes champions when they won 1 and lost 1.  


Scenario #2
Let's say we have Team A, B, C and the results as follows:
Team A beats Team B by 3:2
Team A beats Team C by 3:2
Team B beats Team C by 4:1

Then the total points scored will be:
Team A: 22 points
Team B: 22 points
Team C: 16 points
In the above situation which team will become champions since both Team A & B have 22 points each? We need a more detail "tie break" description to determine which team will become champions.

[ 本帖最後由 wlwlwl 於 2009-11-27 10:12 編輯 ]
wlwlwl
Forehand: inverted
Backhand: Tibhar Grass Dtecs

TOP

Scenario #1
Yes, 無錯.  end up Team#B will be champion in this situation
我們的比賽有別於平時的團体賽, 每一 team 實力必須平均才能取勝

Scenarto #2
如同分, then 勝者為勝. 如三隊都同分, 那麼便要計細分
香港乒乓網
查詢電話:97020720
就是忘記背後,努力面前的,向著標竿直跑。腓三:14

TOP

發新話題